What is the volume of natural gas containing 90% methane, which is consumed to obtain 3 mol of nitrobenzene?

Given:
φ (CH4) = 90%
n (С6Н5NO2) = 3 mol

To find:
V (natural gas) -?

Decision:
1) Write a conditional diagram of a chemical reaction:
6CH4 -> C6H5NO2;
2) Calculate the amount of substance CH4:
n (CH4) = (C6H5NO2) * 6 = 3 * 6 = 18 mol;
3) Calculate the volume of CH4:
V (CH4) = n (CH4) * Vm = 18 * 22.4 = 403.2 L;
4) Calculate the volume of natural gas:
V (natural gas) = V (CH4) * 100% / φ (CH4) = 403.2 * 100% / 90% = 448 HP

Answer: The volume of natural gas is 448 liters.



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