What is the volume of nitric oxide (IV) weighing 460 g?

Find the amount of nitrogen dioxide substance:

n (NO2) = m (NO2) / M (NO2) = 460/46 = 10 mol.

Under normal conditions, 1 mol of gas occupies a volume of 22.4 liters. Given this ratio:

V (NO2) = n (NO2) * Vm = 10 * 22.4 = 224 HP

Answer: V (NO2) = 224 liters.

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