What is the volume of one mole of an ideal gas under normal conditions T = 273k, p = 101325Pa?
| July 14, 2021 | education
To determine the value of the volume of 1 mole of an ideal gas taken under normal conditions, we apply the formula: Pnu * V = ν * R * Tnu, from where we can express: V = ν * R * Tnu / Phnu.
Constants and variables: ν is the number of mol of gas (ν = 1 mol); R – universal gas constant (R = 8.31 J / (mol * K)); Tnu – temperature (by condition Tnu = 273 K); Рnu – gas pressure (according to the condition Рnu = 101325 Pa).
Calculation: V = ν * R * Tn / Rn = 1 * 8.31 * 273/101325 = 22.39 * 10-3 m3 = 22.39 dm3.
Answer: The volume that 1 mole of the taken ideal gas should occupy is 22.39 dm3.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
