What is the volume of oxygen required for the combustion of 2.24L of carbon oxide (II)?
May 1, 2021 | education
| The oxidation reaction of carbon monoxide is described by the following chemical reaction equation:
CO + ½ O2 = CO2;
1 mole of carbon monoxide reacts with ½ mole of oxygen. This synthesizes 1 mol of carbon dioxide.
Let’s determine the chemical amount of a substance in 2.24 liters of carbon monoxide.
To do this, we divide the volume of gas by the volume of 1 mole of gas.
N CO = 2.24 / 22.4 = 0.1 mol;
To oxidize such an amount of a substance, you need 0.1 / 2 = 0.05 mol of oxygen.
Let’s define its volume.
To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).
V O2 = 0.05 x 22.4 = 1.12 liters;
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