What is the volume of oxygen required to burn 32 g of hydrogen?

Given:
m (H2) = 32 g

Find:
V (O2) -?

Solution:
1) Write the equation of a chemical reaction:
O2 + 2H2 => 2H2O;
2) Using the periodic system of D.I.Mendeleev, calculate the molar mass of H2:
M (H2) = Mr (H2) = Ar (H) * N (H) = 1 * 2 = 2 g / mol;
3) Calculate the amount of substance H2:
n (H2) = m (H2) / M (H2) = 32/2 = 16 mol;
4) Determine the amount of substance O2:
n (O2) = n (H2) / 2 = 16/2 = 8 mol;
5) Calculate the volume of O2:
V (O2) = n (O2) * Vm = 8 * 22.4 = 179.2 liters.

Answer: The O2 volume is 179.2 liters.