What is the volume of sulfur dioxide generated by the combustion of 67.2 liters of hydrogen sulfide?

univerkov | January 17, 2021 | education

Given:
V (H2S) = 67.2 l
Find: V (SO2)
Decision:
2H2S + 3O2 = 2SO2 + 2H2O
n (H2S) = V / Vm = 67.2 L / 22.4 L / mol = 3 mol
n (H2S): n (SO2) = 1: 1
n (SO2) = 3 mol
V (SO2) = n * Vm = 3 mol * 22.4 L / mol = 67.2 L
Answer: 67.2 l

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