What is the weight of a 250cc brass part in oil?

Weight in oil is equal to the difference between gravity and Archimedes’ buoyancy.
P = Ft – Fa = m * g – ρn * g * V, where m is the mass of the part (m = ρl * V; ρl is the density of brass, ρl = 8500 kg / m ^ 3; V is the volume of the part, V = 250 cm ^ 3 = 250 * 10 ^ -6 m ^ 3), g – acceleration of gravity (g = 10 m / s ^ 2), ρн – oil density (ρн = 800 kg / m ^ 3).
Let’s calculate the weight of a brass part in oil:
P = m * g – ρn * g * V = ρl * V * g – ρn * g * V = 8500 * (250 * 10 ^ -6) * 10 – 800 * 10 * (250 * 10 ^ -6) = 21.25 – 2 = 19.25 N
Answer: The weight of the brass part in oil is 19.25 N.