What is the weight of a brick weighing 4 kg in kerosene if the density of the brick

What is the weight of a brick weighing 4 kg in kerosene if the density of the brick is 2500 kg / m3 and the density of kerosene is 900 kg / m3.

Data: m (mass of the brick taken) = 4 kg; for the calculation, we assume that the brick is completely immersed in kerosene.

Constants: g (acceleration due to gravity) ≈ 10 m / s2; by condition ρ1 (brick density) = 2500 kg / m3; ρ2 (kerosene density) = 900 kg / m3.

The weight of the brick taken in kerosene is determined by the formula: P = Fт – Fa = m * g – ρ2 * g * V = m * g – ρ2 * g * m / ρ1 = m * g * (1 – ρ2 / ρ1).

Let’s calculate: P = 4 * 10 * (1 – 900/2500) = 25.6 N.

Answer: The weight of the taken brick in kerosene is 25.6 N.