What is the weight of a person in an elevator descending with an acceleration of 10m / s ^ 2
| May 9, 2021 | education
What is the weight of a person in an elevator descending with an acceleration of 10m / s ^ 2 and a mass of 60kg g = 10m / s ^ 2?
To determine the value of a person’s weight during an accelerated descent of the elevator down, we apply the formula: P = mh * (g – a).
Variables and constants: mh – human weight (mh = 60 kg); g – acceleration due to gravity (g ≈ 10 m / s2); a is the acceleration of the elevator (a = 10 m / s2).
Calculation: P = mh * (g – a) = 60 * (10 – 10) = 0 N (weightless state).
Answer: The weight of a person in a descending elevator is zero.
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