What is the width of the rectangle, the length of which is 8 cm, and the perimeter is 20 cm? find the square of the square.

Let’s denote by x the width of this rectangle. The perimeter of a rectangle is twice the length and width of this rectangle. According to the condition of the problem, the length of this rectangle is 8 cm, and the perimeter is 20 cm, therefore, the following relationship is true:
2 * (x + 8) = 20.
We solve the resulting equation:
2 * x + 16 = 20;
2 * x = 20 – 16;
2 * x = 4;
x = 4/2;
x = 2.
Find the area of the given rectangle S:
S = 2 * 8 = 16 sq. Cm.

Answer: the width of this rectangle is 2 cm, the area of this rectangle is 16 sq. Cm.