What is the work of the current in the electric motor during 1.5 minutes

What is the work of the current in the electric motor during 1.5 minutes, if at a voltage of 220 V the current in the motor winding is 200 mA?

Task data: t (duration of the used electric motor) = 1.5 min (in SI system t = 90 s); U (mains voltage) = 220 V; I (winding current) = 200 mA (0.2 A).

To determine the work of the current in the used electric motor, we use the Joule-Lenz law: A = U * I * t.

Let’s make a calculation: A = 220 * 0.2 * 90 = 3960 J.

Answer: For 1.5 minutes of operation of the electric motor used, the current work was 3960 J.