What is the work of the force of gravity acting on a person weighing 80 kg when descending

What is the work of the force of gravity acting on a person weighing 80 kg when descending one floor, if its length is 10 m and the height of the floor is 3.5 m?

Since the work of gravity will depend only on the initial and final position of the specified person, we will calculate its work by the formula: A = Ft * S = mh * g * h.

Constants and variables: mh – the mass of the person represented (mh = 80 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h – floor height (h = 3.5 m).

Calculation: A = mh * g * h = 80 * 10 * 3.5 = 2.8 * 103 J.

Answer: The work of the force of gravity acting on the specified person is 2.8 kJ.