What is the work of the force of gravity acting on a stone weighing 4 kg, when it falls from a height of 500 m in a mountain gorge to a ledge located at an altitude of 100 m?
Task data: m (the mass of the fallen stone) = 4 kg; h1 (initial height of the stone) = 500 m; h2 (ledge height) = 100 m.
Reference values: g (acceleration due to gravity) ≈ 10 m / s2.
The work of gravity when the stone in question falls is determined by the formula: A = ΔEp = En1 – En2 = m * g * h1 – m * g * h2 = m * g * (h1 – h2).
Let’s calculate: A = 4 * 10 * (500 – 100) = 16 * 10 ^ 3 J (16 kJ).
Answer: When the stone in question fell, gravity performed a work of 16 kJ.
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