What is the work that must be spent on stretching the dynamometer spring from the middle of the scale

What is the work that must be spent on stretching the dynamometer spring from the middle of the scale to the extreme division, if the dynamometer is designed for an ultimate load of 100 N, and its spring rate is 1000 N / m?

The condition indicates half of the dynamometer measurement scale, so we take half m, e 50H.

We write down what is given and proceed to solving the problem.

Given: F = 50n; k = 1000n / m;

Find: A-?

F = kx from this formula we find the length of tension of the spring.

x = F / k x = 50/1000 = 0.05 meters; work formula for this problem A = Fx

Find a job: A = 50 × 0.05 = 2.5 (J) joule.

Answer: A = 2.5J



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