What kind of movement does the body pass in a tenth second, moves with an acceleration of 0.4 m / s ^ 2?

The path traversed by the body during uniformly accelerated motion is determined by the formula S = v start * t + (at²) / 2, where S is the path, distance, v initial is the initial speed, t is time.

The initial speed in our case is not important, we need to find a specific path of the body, traversed in a certain time. Therefore, we use the formula for the path, for uniformly accelerated motion with zero initial speed – S = (at²) / 2.

Substituting these values ​​for us, we get – (0.4 m / s² * (0.1 s) ²) / 2 = 0.004 m / 2 = 0.002 m.

Answer: the body will travel 0.002 m or 0.2 centimeters in one tenth of a second with the acceleration indicated in our example.



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