What kind of pressure does a girl, weighing 42 kg, exert on the floor; the area of each sole of her shoes is 210 cm2?

m = 42 kg.
g = 9.8 m / s2.
S1 = 210 cm2 = 0.021 m2.
P -?
Pressure P is the ratio of the force F to the area S of the surface on which this force acts: P = F / S.
The girl acts on the surface of the earth by the force of her weight, the value of which is determined by the formula: F = m * g.
Since the girl has two legs and each shoe sole has an area S1, the girl’s weight is distributed over the area S = 2 * S1.
The girl’s pressure P will be determined by the formula: P = m * g / 2 * S1.
P = 42 kg * 9.8 m / s2 / 2 * 0.021 m2 = 9800 Pa.
Answer: the girl’s pressure is P = 9800 Pa.