What kind of self-induction ed arises in a coil with an inductance of 50m2n, if the current

What kind of self-induction ed arises in a coil with an inductance of 50m2n, if the current in it increases from 5mA to 15mA in 2ms?

Initial data: L (coil inductance) = 50 mH (50 * 10-3 H); I1 (initial current in the coil) = 5 mA (5 * 10-3 A); I2 (end current) = 15 mA (15 * 10-3 A); Δt (duration of current rise) = 2 ms (2 * 10-3 s).

EMF of self-induction, which has arisen in the considered coil, is determined by the formula: ε = | L * ΔI / Δt | = | L * (I2 – I1) / Δt |.

Calculation: ε = 50 * 10-3 * (15 * 10-3 – 5 * 10-3) / (2 * 10-3) = 0.25 V.

Answer: In the considered coil, an EMF of self-induction of 0.25 V.