What kind of work does a person do when lifting a 2 kg load to a height of 1.5 m if the load moves evenly?

To determine the work that a person performed with a uniform lifting of the load (a = 0 m / s2), we use the formula: A = F * S = ΔEp = m * g * h, where m is the mass of the load (m = 2 kg); g – acceleration due to gravity (constant value, g ≈ 10 m / s2); h – lifting height (h = 1.5 m).

Let’s calculate: A = 2 * 10 * 1.5 = 30 J.

Answer: With a uniform lifting of the load, a person performed work of 30 J.