What kind of work does a person do when lifting a load weighing 16 kg to a height of 10 m?

In the case of uniform movement of the load, the work done by a person will be equal to the change in the potential energy of the load: A = ΔEp = m * g * h, where m is the mass of the load (m = 16 kg); g – acceleration due to gravity (constant value, g ≈ 10 m / s2); h is the height to which the load was lifted (h = 10 m).

Let’s perform the calculation: A = m * g * h = 16 * 10 * 10 = 1.6 * 10 ^ 3 J (1.6 kJ).

Answer: When lifting a load, a person performed work equal to 1.6 kJ.