What kind of work does an electric locomotive perform when the speed increases with a mass of 3000 tons from 54 to 72 km / h.
| December 20, 2020 | education
Data: V1 (initial speed) = 36 km / h; V2 (final speed) = 54 km / h; m (train weight) = 3000 t.
SI system: V1 = 36 km / h = 10 m / s; V2 = 54 km / h = 15 m / s; m = 3000 t = 3000 * 103 kg = 3 * 106 kg.
The work that the electric locomotive will do is equal to the difference between the final and initial kinetic energies of the train: A = Ek2 – Ek1 = 0.5 * m * V22 – 0.5 * m * V12 = 0.5 * m * (V22 – V12).
Calculation: A = 0.5 * 3 * 106 * (152 – 102) = 0.5 * 3 * 106 * (225 – 100) = 0.5 * 3 * 106 * 125 = 187.5 * 106 J = 187 , 5 MJ.
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