What kind of work does the electric current do in the electric motor of the vacuum cleaner in 0.5

What kind of work does the electric current do in the electric motor of the vacuum cleaner in 0.5 hours of work if the vacuum cleaner is connected to a city network with a voltage of 220V and the current strength in the network is 0.5A?

Given: t (duration of the vacuum cleaner) = 0.5 h (in the SI system t = 1800 s); U (voltage in the city network) = 220 V; I (current in the network) = 0.5 A.

The work done by the current in the electric motor of the vacuum cleaner is calculated using the Joule-Lenz law: A = U * I * t.

Let’s make a calculation: A = 220 * 0.5 * 1800 = 198 * 10 ^ 3 J (198 kJ).

Answer: In the electric motor of the vacuum cleaner, the current has done work of 198 kJ.