What kind of work is done when a stone with a volume of 0.6 m3 is evenly lifted to a height

What kind of work is done when a stone with a volume of 0.6 m3 is evenly lifted to a height of 15 m? stone density 2500km / m3

V = 0.6 m ^ 3.

h = 15 m.

ρ = 2500 kg / m ^ 3.

g = 9.8 m / s ^ 2.

A – ?

Mechanical work A is determined by the formula: A = F * S * cosα, where F is the force, S is the movement of the body, in our case the height h, ∠α is the angle between F and S.

∠α = 0, cos0 = 1.

Since the stone rises evenly in a straight line, the force F with which the stone is lifted is equal to the gravity m * g.

F = m * g.

Let’s find the mass of the body by the formula: m = ρ * V, where ρ is the density of the substance from which the body is made, V is the volume of the body.

A = ρ * V * g * h.

A = 2500 kg / m ^ 3 * 0.6 m ^ 3 * 9.8 m / s ^ 2 * 15 m = 220500 J.

Answer: A = 220500 J.