What kind of work will a 6 kW hoist do in 30 minutes of work?

The power of the lift can be calculated using the formula:
N = A / t, where N is the power of the lift (N = 6 kW = 6 * 10 ^ 3 W), A is the mechanical work performed by the lift (J), t is the operating time of the lift (t = 30 min = 1800 s).
Let us express from the formula and calculate the mechanical work of the lift:
A = N * t = (6 * 10 ^ 3) * 1800 = 10,800,000 J = 10.8 * 10 ^ 6 J = 10.8 MJ.
Answer: The mechanical work of the hoist is 10.8 MJ.