What kinetic energy does a bullet weighing 200 grams have if it has traveled 1 km in 5 minutes?
| July 11, 2021 | education
Task data: m (bullet weight) = 200 g (0.2 kg); t (duration of the bullet flight) = 5 min (300 s); S (distance traveled by the bullet) = 1 km (10 ^ 3 m).
The kinetic energy possessed by a bullet in flight is determined by the formula: Ek = m * V ^ 2/2 = m * (S / t) ^ 2/2 = m * S ^ 2 / (2 * t ^ 2).
Calculation: Ek = 0.2 * (10 ^ 3) ^ 2 / (2 * 300 ^ 2) = 1.11 J.
Answer: The bullet in flight had a kinetic energy of 1.11 J.
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