What kinetic energy K does a body of mass m = 1 kg have, falling without initial velocity

| April 25, 2021 | education

What kinetic energy K does a body of mass m = 1 kg have, falling without initial velocity, after a time t = 5 s after the beginning of the fall?

V0 = 0 m / s.

m = 1 kg.

g = 10 m / s2.

t = 5 s.

Ek -?

The kinetic energy of the body Ek is determined by the formula: Ek = m * V ^ 2/2, where m is the mass of the body, V is the speed of its movement.

Since when falling, the body moves uniformly accelerated with the acceleration of gravity g, the speed of the body is expressed by the formula: V = V0 + g * t.

Since the body falls freely V0 = 0 m / s, the formula will take the form: V = g * t.

V = 10 m / s2 * 5 s = 50 m / s.

Substitute the data from the condition of the problem: Ek = 1 kg * (50 m / s) ^ 2/2 = 1250 J.

Answer: the kinetic energy of the body is Ek = 1250 J.



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