What kinetic energy must be imparted to a body weighing 0.5 kg in order for it to rise vertically upward by 10 m?

m = 0.5 kg.

g = 10 N / kg.

h = 10 m.

Ek -?

V -?

Since, according to the condition of the problem, the air resistance can be neglected, the law of conservation of total mechanical energy is valid when the body moves. Since the body is thrown from the surface of the earth, it has only kinetic energy Ek. The kinetic energy of the body Ek is determined by the formula: Ek = m * V ^ 2/2.

The kinetic energy of the body Ek transforms into potential energy En, and at the maximum height the body stops, at this moment the body has only potential energy: Ek = En.

The potential energy of a body is determined by the formula: En = m * g * h.

Ek = m * g * h.

Ek = 0.5 kg * 10 N / kg * 10 m = 50 J.

m * V ^ 2/2 = m * g * h.

V = √ (2 * g * h).

V = √ (2 * 10 N / kg * 10 m) = 14.1 m / s.

Answer: the body must have kinetic energy Ek = 50 J and have a velocity V = 14.1 m / s.