What m (CaO) is formed during the decomposition of 250 g CaCO3 containing 20% impurities. What kind of V (CO2) is formed?

Decomposition reaction: CaCO3 = CaO + CO2.
1) Find the mass of impurities in calcium carbonate. We multiply the mass of carbonate by 20% and divide by 100%: 250 * 20/100 = 50g.
2) The mass of pure carbonate substance is: 250 – 50 = 200g.
3) Find the amount of calcium carbonate substance. To do this, divide the mass of the pure carbonate substance by its molar mass: 200/100 = 2 mol.
4) According to the reaction equation, there is one mole of carbon dioxide per mole of calcium carbonate. This means that the amount of carbon dioxide substance is also 2 mol.
5) The volume of carbon dioxide is: 2 * 22.4 = 44.8 liters – the answer.