What mass and amount of Al was required for the reaction with hydrochloric acid if 5.6 (L) H2 was formed?

The equation of the proceeding reaction:
2Al + 6HCl = 2AlCl3 + 3H2.
1) Find the amount of substance hydrogen. To do this, divide the volume of hydrogen by the molar volume: 5.6 / 22.4 = 0.25 mol.
2) According to the reaction equation, there are two moles of aluminum for three moles of hydrogen. This means that the amount of aluminum substance is: 3 * 0.25 / 2 = 0.375 mol – the answer.
3) Determine the molar mass of aluminum according to the periodic table: 27.
4) Find the mass of aluminum. For this, the amount of aluminum substance is multiplied by its molar mass: 0.375 * 27 = 10.125 g – the answer.