What mass and amount of sulfuric acid reacts with 200 g of sodium hydroxide containing 10 percent impurities?

Let’s implement the solution:

We compose the equation of the process:
H2SO4 + 2NaOH = Na2SO4 + 2H2O – ion exchange, formed ferrous sulfate, water;

Calculations:
M (H2SO4) = 98 g / mol;

M (NaOH) = 39.9 g / mol;

m (NaOH) = 200 * (1 – 0.10) = 180 g (mass without impurities);

Y (NaOH) = m / M = 180 / 39.9 = 4.5 mol.

Determine the proportion:
X mol (H2SO4) – 4.5 mol (NaOH);

-1 mol – 2 mol hence, X mol (H2SO4) = 1 * 4.5 / 2 = 2.25 mol.

Find the mass of acid:
m (H2SO4) = Y * M = 2.25 * 98 = 220.5 g

Answer: the mass of sulfuric acid is 220.5 g