What mass and volume of carbon dioxide can be obtained by combustion a) 5 mol of acetylene;

What mass and volume of carbon dioxide can be obtained by combustion a) 5 mol of acetylene; what is the number of molecules? b) portions of ethane 0.3 * 10 ^ 23 molecules; what is the amount of substance?

a) n (C2H4) = 5 mol.
C2H4 + 3O2 = 2CO2 + 2H2O
5 mol С2Н4 – х mol СО2
1 mol С2Н4 – 2 mol СО2
X = 5 * 2: 1 = 10 mol CO2.
N = n * Na.
N = 10 * 6.02 * 10’23 = 6.02 * 10’24 molecules.
n = m / M.
m = n * M.
M (CO2) = 12 + 16 * 2 = 44 g / mol.
m = 10 * 44 = 440 g.
n = V / Vm.
V = n * Vm = 10 * 22.4 = 224 liters of CO2.

b) N (C2H6) = 0.3 * 10’23 molecules.
N = n * Na.
n = N / Na = 0.3 * 10’23 / 6.02 * 10’23 = 0.3 / 6.02 = 0.0498 mol.
2C2H6 + 7O2 = 4CO2 +6 H2O
n (CO2) = 0.498 * 4: 2 = 0.0997 mol.
m (CO2) = n * M = 0.0997 * 44 = 4.4 g.
V = n * Vm = 0.0997 * 22.4 = 2.233 liters of CO2.



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