What mass and volume of carbon dioxide is emitted when treating 50 g of calcium carbonate with hydrochloric acid?

The equation for the reaction of calcium carbonate with hydrochloric acid:

CaCO3 + 2HCl = CaCl2 + CO2 + H2O

Amount of calcium carbonate substance:

v (CaCO3) = m (CaCO3) / M (CaCO3) = 50/100 = 0.5 (mol).

According to the reaction equation, 1 mol of CO2 is formed from 1 mol of CaCO3, therefore:

v (CO2) = v (CaCO3) = 0.5 (mol).

The mass of the generated carbon dioxide:

m (CO2) = v (CO2) * M (CO2) = 0.5 * 44 = 22 (g).

The volume of carbon dioxide evolved under normal conditions (n.a.):

V (CO2) = v (CO2) * Vm = 0.5 * 22.4 = 11.2 (L).