What mass and volume of carbon dioxide is released when treating 50 g of calcium carbonate with sulfuric acid?
| November 20, 2020 | education
Let’s write the reaction equation: CaCO3 + H2SO4 = CaSO4 + H2O + CO2
Let’s find the amount of calcium carbonate substance: 50/100 = 0.5 (mol)
According to the equation, the amount of calcium carbonate substance is equal to the amount of carbon dioxide substance.
We calculate the mass of carbon dioxide: 44 * 0.5 = 22 (g)
Let’s calculate the volume of carbon dioxide: 0.5 * 22.4 = 11.2 (l)
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