What mass g of salt is formed by the interaction of 200 g of an 8.55% solution of barium hydroxide
What mass g of salt is formed by the interaction of 200 g of an 8.55% solution of barium hydroxide with hydrochloric acid? This produces barium chloride and water.
The equation of the proceeding reaction:
Ba (OH) 2 + 2HCl = BaCl2 + 2H2O.
1) Find the mass of the solute barium hydroxide. To do this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 200 * 8.55 / 100 = 17.1 g.
2) Find the molar mass of barium hydroxide: 137 + 32 + 2 = 171.
3) Find the amount of barium hydroxide substance. To do this, divide the mass of barium by its molar mass: 17.1 / 171 = 0.1 mol.
4) According to the reaction equation, the amount of barium chloride substance is 0.1 mol.
5) The mass of barium chloride is: 0.1 * (137 + 35.5 * 2) = 20.8 g – the answer.