What mass (in grams) of salt is formed when 3.25 nitric acid is neutralized with potassium hydroxide?

Given:
m (HNO3) = 3.25 g

Find:
m (salt) -?

Solution:
1) Write the reaction equation:
HNO3 + KOH => KNO3 + H2O;
2) Calculate the molar masses of HNO3 and KNO3:
M (HNO3) = Mr (HNO3) = Ar (H) + Ar (N) + Ar (O) * 3 = 1 + 14 + 16 * 3 = 63 g / mol;
M (KNO3) = Mr (KNO3) = Ar (K) + Ar (N) + Ar (O) * 3 = 39 + 14 + 16 * 3 = 101 g / mol;
3) Calculate the amount of substance HNO3:
n (HNO3) = m (HNO3) / M (HNO3) = 3.25 / 63 = 0.052 mol;
4) Determine the amount of KNO3 substance:
n (KNO3) = n (HNO3) = 0.052 mol;
5) Calculate the mass of KNO3:
m (KNO3) = n (KNO3) * M (KNO3) = 0.052 * 101 = 5.25 g.

Answer: The mass of KNO3 is 5.25 g.