What mass is calcium carbonate formed by the interaction of 100 g calcium oxide with 100 g carbon dioxide?

| May 25, 2021 | education

Answer: m (CaCO3) = 178.6 g.
Explanation of the solution to the problem: in order to solve this problem, you first need to write the equation of the chemical reaction: CaO + CO2 => CaCO3.
Then you need to find the amount of calcium oxide substance and carbon dioxide, respectively (we divide the mass by the molar mass):
n (CaO) = m / M = 100/56 = 1.786 g.
n (CO2) = m / M = 100/44 = 2.27 g.
The reaction shows that they interact in a 1: 1 ratio, so carbon dioxide is in excess. This means that further calculation must be carried out for calcium oxide.
We find the amount of calcium carbonate substance, it is equal to the amount of calcium oxide substance:
n (CaCO3) = n (CaO) = 1.786 g.
The last step is to find the mass of calcium carbonate, for this we multiply the found amount of the substance of calcium carbonate by its molar mass:
m (CaCO3) = n * M = 1.786 * 100 = 178.6 g.



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