What mass is the salt formed during the interaction of 49.6 Ca hydroxide and 6.7 g of sulfuric acid?

Let’s write the equation of the salt formation reaction:
Ca (OH) 2 + H2SO4 = CaSO4 + 2H2O.
Determine the number of moles of starting materials:
n (Ca (OH) 2) = 49.6 / 74 = 0.67 mol.
n (H2SO4) = 6.7 / 98 = 0.07 mol.
By the number of moles, calcium hydroxide is in excess, so we decide by the lack:
6.7 g H2SO4 – 98 g / mol.
x g CaSO4 – 136 g / mol.
Find x and get the mass of salt:
x = 6.7 * 136/98 = 9.3 g.