What mass of 10% h2so4 solution is required to completely neutralize 8 g of naoh?

Sodium hydroxide neutralization equation: 2NaOH + H2SO4 = Na2SO4 + 2H2O.
1) Add the atomic masses of the components of the sodium hydroxide substance to find the molar mass: 23 + 16 + 1 = 40.
2) Divide the mass of sodium hydroxide by the molar mass to find the amount of the substance: 8/40 = 0.2 mol.
3) Find the amount of sulfuric acid substance. To do this, consider the reaction equation. For two moles of sodium hydroxide, there is one mole of sulfuric acid. This means that the amount of sulfuric acid substance is: 2 * 0.2 = 0.4 mol.
4) The molar mass of sulfuric acid is: 2 + 32 + 16 * 4 = 98.
5) The mass of the sulfuric acid solution is: 98 * 100/10 = 980g – the answer.

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