What mass of 10% hydrochloric acid solution is required to dissolve 60 g of calcium carbonate?

The reaction of interaction of calcium carbonate with hydrochloric acid is described by the following chemical reaction equation:

CaCO3 + 2HCl = CaCl2 + H2O + CO2;

One mole of calcium carbonate reacts with two moles of hydrochloric acid.

Determine the amount of substance in 60 grams of calcium carbonate.

Its molar mass is:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of substance will be:

N CaCO3 = 60/100 = 0.6 mol;

To dissolve such an amount of a substance, 1.2 mol of hydrochloric acid will be required.

Let’s find its mass and the mass of its 10% solution.

M HCl = 1 + 35.5 = 36.5 grams / mol;

m HCl = 36.5 x 1.2 = 43.8 grams;

m HCl solution = 43.8 / 0.1 = 438 grams;