What mass of 10% sulfuric acid is required to absorb 11.2 L of NH3 under normal conditions?

2NH3 + H2SO4 → (NH4) 2SO4

Ammonia amount n (NH3) = V (NH3): Vm = 11.2: 22.4 = 0.5 mol (Vm is a constant value, the volume of 1 mol of gas)

According to the equation, the ratio of the amount of ammonia to the amount of sulfuric acid n (NH3): n (H2SO4) = 2: 1 = 0.5: 0.25. That is, the amount of sulfuric acid n (H2SO4) = 0.25 mol

M (H2SO4) = 2 × Ar (H) + 1 × Ar (S) + 4 × Ar (O) = 2 × 1 + 1 × 32 + 4 × 16 = 98 g / mol

m (H2SO4) = n (H2SO4) × M (H2SO4) = 0.25 × 98 = 24.5 g

m solution (H2SO4) = 24.5 g × 100%: 10% = 245 g