What mass of 31.5% nitric acid will be used to obtain 4.7 g of copper (II) nitrate from copper (II) oxide?

univerkov | January 17, 2021 | education

Given:
w (HNO3) = 31.5% = 0.315
m (Cu (NO3) 2) = 4.7 g
To find:
m (HNO3)
Decision:
CuO + 2HNO3 = Cu (NO3) 2 + H2O
n (Cu (NO3) 2) = m / M = 4.7 g / 188 g / mol = 0.025 mol
n (Cu (NO3) 2): n (HNO3) = 1: 2
n (HNO3) = 0.025 mol * 2 = 0.05 mol
m (HNO3) = n * M = 0.05 mol * 63 g / mol = 3.15 g
Answer: 3.15 g

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