What mass of 60% sulfuric acid is required to obtain 8 g of copper (II) sulfate from copper (II) oxide?

univerkov | August 22, 2021 | education

The equation of the ongoing reaction: CuO + H2SO4 = CuSO4 + H2O.
Progress in solving the problem:
1. Determination of the molar mass of copper sulfate according to the periodic table.
2. Calculation of the amount of copper sulfate substance.
3. Determination of the amount of sulfuric acid substance according to the reaction equation.
4. Determination of the molar mass of sulfuric acid.
5. Calculation of the mass of the solute of sulfuric acid in its solution.
6. Determination of the desired mass of sulfuric acid solution.
Solution:
1.64 + 32 + 16 * 4 = 160.
2.8/160 = 0.05 mol.
3.0.05 mol.
4.1 * 2 + 32 + 16 * 4 = 98.
5.88 * 0.05 = 4.9g.
6.49 * 100/60 = 8.2g – the answer.

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