What mass of a 10% sodium hydroxide solution is required to neutralize 20 g

| August 12, 2021 | education

What mass of a 10% sodium hydroxide solution is required to neutralize 20 g of sulfuric acid solution with a mass fractions of sulfuric acid 0.049?

2KOH + H2SO4 = K2SO4 + 2H2O.
1) Find the mass of the solute of sulfuric acid: 0.049 * 20 = 0.98 g.
2) We calculate the molar mass of sulfuric acid according to the periodic table: 1 * 2 + 32 + 4 * 16 = 98.
3) Find the amount of sulfuric acid substance: 0.98 / 98 = 0.01 mol.
4) According to the reaction equation, there are two moles of potassium hydroxide per mole of sulfuric acid. This means that the amount of potassium hydroxide substance is: 0.01 / 2 = 0.005 mol.
5) Molar mass of potassium hydroxide: 39 + 1 + 16 = 56.
6) Mass of potassium hydroxide: 56 * 0.005 = 0.28g.
7) Mass of potassium hydroxide solution: 0.28 * 100/10 = 2.8 g – answer.



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