What mass of a 10% sulfuric acid solution is required to neutralize 28 g of a 5% potassium hydroxide solution?

H2SO4 + 2KOH = K2SO4 + 2H2O.
1) Find the mass of the potassium hydroxide solute. To do this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 28 * 5/100 = 1.4 g.
2) Molar mass of potassium hydroxide: 39 + 1 + 16 = 56.
3) The amount of potassium hydroxide substance: 1.4 / 56 = 0.025 mol.
4) According to the reaction equation, there is one mole of sulfuric acid for two moles of potassium hydroxide. This means that the amount of sulfuric acid substance is: 0.025 * 2 = 0.05 mol.
5) Molar mass of sulfuric acid: 98.
6) Mass of sulfuric acid solute: 98 * 0.05 = 4.9 g.
7) Mass of sulfuric acid solution: 490/10 = 49g – answer.