What mass of a 12% glucose solution will react with copper2 hydroxide when heated, if as a result 30 g

What mass of a 12% glucose solution will react with copper2 hydroxide when heated, if as a result 30 g of precipitate is released?

Given:
ω (C6H12O6) = 12%
m (sediment) = 30 g

To find:
m solution (C6H12O6) -?

1) C6H12O6 + 2Cu (OH) 2 => C6H12O7 + Cu2O ↓ + 2H2O;
2) n (Cu2O) = m / M = 30/144 = 0.2 mol;
3) n (C6H12O6) = n (Cu2O) = 0.2 mol;
4) m (C6H12O6) = n * M = 0.2 * 180 = 36 g;
5) m solution (C6H12O6) = m * 100% / ω = 36 * 100% / 12% = 300 g.

Answer: The mass of the C6H12O6 solution is 300 g.