What mass of a 15% hydrochloric acid solution is required to dissolve 10.7 g of iron hydroxide 3.

x g 10.7g
6HCl + 2Fe (OH) 3 = 2FeCl3 + 3H2O
219 g 214 g

x = 219 10.7 / 214 = 10.95g

10.95 g – 15%
x g – 100%
x = 10.95 100/15 = 73 g



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