What mass of a 20% phosphoric acid solution is required to interact with a solution containing 72 g of sodium hydroxide?
H3PO4 + 3NaOH = Na3PO4 + 3H2O.
1) According to the periodic table, we calculate the molar mass of sodium hydroxide: 23 + 16 + 1 = 40.
2) Find the amount of sodium hydroxide substance. To do this, divide the mass of the hydroxide by the molar mass: 72/40 = 1.8 mol.
3) According to the reaction equation, there is one mole of phosphoric acid for three moles of sodium hydroxide. This means that the amount of phosphoric acid substance is: 1.8 * 3 = 5.4 mol.
4) Molar mass of phosphoric acid: 3 + 31 + 64 = 98.
5) Mass of phosphoric acid: 98 * 5.4 = 529g.
6) Find the mass of the solution. To do this, we multiply the mass of phosphoric acid by one hundred percent and divide by the mass fraction of the substance: 529 * 100/20 = 2645g – the answer.
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