What mass of a 30% soda solution can be obtained from 20 g of this substance? How much water is needed for this?

m solution (soda) = m (soda) * 100% / ω (soda) = 20 * 100% / 30% = 66.7 g;
m (water) = m solution (soda) – m (soda) = 66.7 – 20 = 46.7 g.



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