What mass of a solution with a mass fraction of nitric acid of 63% is required for the reaction with copper oxide 16 grams.

CuO + 2HNO3 = Cu (NO3) 2 + H2O
n (CuO) = 16 / (63.5 + 16) = 0.2 mol
hence the amount of acid is 0.4 mol
m (hno3) = 0.4 * 63 = 25.2 g
25.2 g is the mass of the acid itself, then the mass of the solution is: 25.2 * 100: 63 = 40 grams
answer: 40



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