What mass of a solution with a mass fraction of sodium hydroxide of 32% is required to completely neutralize

What mass of a solution with a mass fraction of sodium hydroxide of 32% is required to completely neutralize a solution of nitric acid weighing 50 g with a mass fraction of a dissolved substance of 10%?

Given:
w (NaOH) = 32% = 0.32
m solution (HNO3) = 50 g
w (HNO3) = 10% = 0.1
To find:
m solution (NaOH)
Decision:
NaOH + HNO3 = H2O + NaNO3
m in-islands (HNO3) = w * m solution = 0.1 * 50 g = 5 g
n (HNO3): n (NaOH) = 1: 1
n (NaOH) = 0.08 mol
m in islands (NaOH) = n * M = 0.08 mol * 40 g / mol = 3.2 g
m solution (NaOH) = m in-va / w = 3.2 g / 0.32 = 10 g
Answer: 10 g