What mass of acetaldehyde can be obtained from 11.2 liters of acithelene and 14.4 grams of water

What mass of acetaldehyde can be obtained from 11.2 liters of acithelene and 14.4 grams of water by the Kucherov reaction.

V (C2H2) = 11.2 l m (H2O) = 14.4 g Find: m (CH3-COH) -?
Decision:
1) Write the reaction equation: C2H2 + H2O = (HgSO4, H +) => CH3-COH 2) Find the amount of substance C2H2: n (C2H2) = V (C2H2) / Vm = 11.2 / 22.4 = 0.5 mole; 3) Find the amount of substance H2O: n (H2O) = m (H2O) / Mr (H2O) = 14.4 / 18 = 0.8 mol; 4) Compare the amount of the substance C2H2 and H2O: The amount of the substance C2H2 is in short supply, therefore, the calculations will be carried out for it; 5) Find the amount of CH3-COH substance (taking into account the reaction equation): n (CH3-COH) = n (C2H2) = 0.5 mol; 6) Find the mass of the substance C2H2: m (CH3-COH) = n (CH3-COH) * Mr (CH3-COH) = 0.5 * 44 = 22 g.
Answer: The mass of CH3-COH formed was 22 g.



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